Magnetic Dipole And Axial Field
A small current loop of magnetic moment 0.6A m2 behaves as a magnetic dipole, and a point lies on its axis at a distance of 0.2m from the centre. Treating the loop as a short dipole, what is the magnetic field at that axial point?
Select the correct option:
Solution
1.5×10−5T
A small current loop is equivalent to a magnetic dipole of moment m=NIA, and far along its axis the field mirrors that of a bar magnet: Baxial=4πμ0r32m. This axial field is twice the equatorial field at the same distance, a hallmark of dipole behaviour. Substituting 4πμ0=10−7, m=0.6A m2 and r=0.2m so r3=8×10−3, we get B=10−7×8×10−32(0.6)=10−7×150=1.5×10−5T. The option 0.75×10−5T is the equatorial field, missing the factor of two. The option 3.0×10−5T doubles the moment. The option 6.0×10−5T uses r2 instead of r3. NCERT explicitly establishes this analogy between a current loop and a magnetic dipole. A check confirms the inverse-cube falloff and the 10−5T scale at 20cm. This equivalence between a current loop and a magnetic dipole is one of the most unifying ideas in magnetism, letting the same mathematics describe a tiny coil, a bar magnet, and even an orbiting atomic electron. The factor-of-two relationship between axial and equatorial fields exactly parallels the electric dipole, reinforcing the deep structural similarity between electrostatic and magnetostatic dipole fields that students should carry forward into later chapters. This same dipole field also governs how a compass needle or a small magnet orients itself and oscillates when suspended in an external magnetic field.
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About This Question
- Subject
- physics
- Chapter
- magnetic effects of current and magnetism
- Topic
- magnetic dipole and axial field
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
1.5×10−5T
A small current loop is equivalent to a magnetic dipole of moment m=NIA, and far along its axis the field mirrors that of a bar magnet: Baxial=4πμ0r32m. This axial field is twice the equatorial field at the same distance, a hallmark of dipole behaviour. Substituting 4πμ0=10−7, m=0.6A m2 and r=0.2m so r3=8×10−3, we get B=10−7×8×10−32(0.6)=10−7×150=1.5×10−5T. The option 0.75×10−5T is the equatorial field, missing the factor of two. The option 3.0×10−5T doubles the moment. The option 6.0×10−5T uses r2 instead of r3. NCERT explicitly establishes this analogy between a current loop and a magnetic dipole. A check confirms the inverse-cube falloff and the 10−5T scale at 20cm. This equivalence between a current loop and a magnetic dipole is one of the most unifying ideas in magnetism, letting the same mathematics describe a tiny coil, a bar magnet, and even an orbiting atomic electron. The factor-of-two relationship between axial and equatorial fields exactly parallels the electric dipole, reinforcing the deep structural similarity between electrostatic and magnetostatic dipole fields that students should carry forward into later chapters. This same dipole field also governs how a compass needle or a small magnet orients itself and oscillates when suspended in an external magnetic field.
This medium difficulty physics question is from the chapter magnetic effects of current and magnetism, covering the topic of magnetic dipole and axial field. It appeared in the 2025 exam.
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