Locus In Argand Plane
The set of all complex numbers z satisfying the equation given by the ratio condition arg of the quantity (z - 1)/(z + 1) equal to π/2 forms which curve, excluding endpoints?
Select the correct option:
Solution
A semicircle of radius 1 centred at origin
The argument of a ratio (z - a)/(z - b) measures the directed angle subtended at z by the segment from a to b, a powerful JEE Advanced locus tool. Setting arg((z - 1)/(z + 1)) = π/2 means the segment joining the points 1 and -1 subtends a right angle at z. By the converse of the angle-in-semicircle theorem, the locus of points seeing a fixed segment at 90 degrees is the circle whose diameter is that segment. The segment from -1 to 1 has midpoint at the origin and length 2, so the circle has centre 0 and radius 1. The fixed sign of the argument restricts z to one side, giving a semicircle, with the diameter endpoints excluded since the ratio is undefined there. Option full circle ignores the sign restriction. Option straight line would arise if the argument were 0 or π. Option parabola has no basis. Hence the locus is a semicircle of radius 1 centred at the origin. Plausibility check: the point z = i gives (i-1)/(i+1) = i, whose argument is π/2, and |i| = 1, confirming i lies on the described semicircle.
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About This Question
- Subject
- mathematics
- Chapter
- complex numbers and quadratic equations
- Topic
- locus in argand plane
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
A semicircle of radius 1 centred at origin
The argument of a ratio (z - a)/(z - b) measures the directed angle subtended at z by the segment from a to b, a powerful JEE Advanced locus tool. Setting arg((z - 1)/(z + 1)) = π/2 means the segment joining the points 1 and -1 subtends a right angle at z. By the converse of the angle-in-semicircle theorem, the locus of points seeing a fixed segment at 90 degrees is the circle whose diameter is that segment. The segment from -1 to 1 has midpoint at the origin and length 2, so the circle has centre 0 and radius 1. The fixed sign of the argument restricts z to one side, giving a semicircle, with the diameter endpoints excluded since the ratio is undefined there. Option full circle ignores the sign restriction. Option straight line would arise if the argument were 0 or π. Option parabola has no basis. Hence the locus is a semicircle of radius 1 centred at the origin. Plausibility check: the point z = i gives (i-1)/(i+1) = i, whose argument is π/2, and |i| = 1, confirming i lies on the described semicircle.
This hard difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of locus in argand plane. It appeared in the 2025 exam.
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