Law Of Equipartition Of Energy
According to the law of equipartition of energy, what average energy is associated with each degree of freedom of a molecule at absolute temperature T?
Select the correct option:
Solution
One-half of Boltzmann constant times temperature
The principle at work is the law of equipartition of energy, stated in NCERT Class 11, Chapter 13 (Kinetic Theory), which asserts that in thermal equilibrium the total energy of a molecule is shared equally among all its degrees of freedom. Each independent quadratic degree of freedom, whether translational or rotational, receives an average energy of exactly 21kBT, where kB is Boltzmann's constant and T is the absolute temperature. This is why a monatomic gas with three translational degrees has average energy 23kBT per molecule. The option 23kBT is the total for three degrees, not the share per single degree. The option kBT doubles the correct value and would only apply to a vibrational mode counting both kinetic and potential terms. The option 31kBT has no basis in the theory. A plausibility check confirms the value: summing 21kBT over f degrees of freedom reproduces the known internal energy 2fkBT per molecule, so the per-degree share of 21kBT is internally consistent.
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About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- law of equipartition of energy
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
One-half of Boltzmann constant times temperature
The principle at work is the law of equipartition of energy, stated in NCERT Class 11, Chapter 13 (Kinetic Theory), which asserts that in thermal equilibrium the total energy of a molecule is shared equally among all its degrees of freedom. Each independent quadratic degree of freedom, whether translational or rotational, receives an average energy of exactly 21kBT, where kB is Boltzmann's constant and T is the absolute temperature. This is why a monatomic gas with three translational degrees has average energy 23kBT per molecule. The option 23kBT is the total for three degrees, not the share per single degree. The option kBT doubles the correct value and would only apply to a vibrational mode counting both kinetic and potential terms. The option 31kBT has no basis in the theory. A plausibility check confirms the value: summing 21kBT over f degrees of freedom reproduces the known internal energy 2fkBT per molecule, so the per-degree share of 21kBT is internally consistent.
This easy difficulty physics question is from the chapter kinetic theory of gases, covering the topic of law of equipartition of energy. It appeared in the 2025 exam.
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