Kolbe's Electrolysis

Process: Electrolysis of an aqueous solution of the salt.
Reaction at Anode: Acetate ion ( $C H_{3} CO O^{-}$ ) loses an electron to form an acetate radical, which decarboxylates into a methyl radical ( $C H_{3}^{.}$ ). Two methyl radicals combine to form Ethane ( $C_{2} H_{6}$ ). $2 C H_{3} CO O^{-} - 2 e^{-} \to 2 C H_{3} CO O^{.} \to 2 C H_{3}^{.} + 2 C O_{2} ↑$ $C H_{3}^{.} + C H_{3}^{.} \to C H_{3} - C H_{3}$
Hydrogen gas is liberated at the cathode.

This medium difficulty chemistry question is from the chapter hydrocarbons, covering the topic of kolbe's electrolysis. It appeared in the 2025 exam.

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Kolbe's Electrolysis

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A hydrocarbon with the molecular formula $C_{6} H_{10}$ is being analysed, and the total number of degr...