Kinetic Interpretation Of Temperature
The average translational kinetic energy of a single gas molecule depends only on absolute temperature; calculate this energy for a molecule at 300 K.
Select the correct option:
Solution
6.21×10−21J
Temperature in kinetic theory is a direct measure of molecular motion, and the average translational kinetic energy of one molecule is KE=23kBT, where kB=1.38×10−23 J/K is the Boltzmann constant. This relation arises because each of the three translational directions contributes 21kBT, and it shows the energy is independent of the gas's identity and mass, depending solely on absolute temperature. Two different gases at the same temperature therefore have molecules with identical average translational energies even though their individual speeds differ. Substituting T=300 K gives KE=23×1.38×10−23×300=6.21×10−21 J. The option 4.14×10−21 J wrongly uses kBT without the factor 3/2. The option 2.07×10−21 J corresponds to only one degree of freedom, 21kBT, not the full translational energy. The option 9.0×10−21 J overestimates by assuming an incorrect temperature near 435 K. This is the standard NCERT result linking the kinetic interpretation of temperature to the equipartition of energy, and it underlies the definition of absolute zero as the state where molecular motion ceases. As a plausibility check, molecular energies at room temperature are of order 10−21 J, fully consistent with our answer.
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About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- kinetic interpretation of temperature
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
6.21×10−21J
Temperature in kinetic theory is a direct measure of molecular motion, and the average translational kinetic energy of one molecule is KE=23kBT, where kB=1.38×10−23 J/K is the Boltzmann constant. This relation arises because each of the three translational directions contributes 21kBT, and it shows the energy is independent of the gas's identity and mass, depending solely on absolute temperature. Two different gases at the same temperature therefore have molecules with identical average translational energies even though their individual speeds differ. Substituting T=300 K gives KE=23×1.38×10−23×300=6.21×10−21 J. The option 4.14×10−21 J wrongly uses kBT without the factor 3/2. The option 2.07×10−21 J corresponds to only one degree of freedom, 21kBT, not the full translational energy. The option 9.0×10−21 J overestimates by assuming an incorrect temperature near 435 K. This is the standard NCERT result linking the kinetic interpretation of temperature to the equipartition of energy, and it underlies the definition of absolute zero as the state where molecular motion ceases. As a plausibility check, molecular energies at room temperature are of order 10−21 J, fully consistent with our answer.
This easy difficulty physics question is from the chapter kinetic theory of gases, covering the topic of kinetic interpretation of temperature. It appeared in the 2025 exam.
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