Kepler's Third Law

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Kepler's third law states T^2 proportional to:

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Kepler's Law of Periods (3rd Law) states: 'The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis (radius for a circle) of its orbit.'
$T^2 \propto r^3$
- Derived by equating $\frac{GMm}{r^2} = m(\frac{2\pi}{T})^2 r \implies T^2 = \frac{4\pi^2}{GM} r^3$.

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Kepler's Third Law

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Two planets have orbital radii r₁ and r₂ = 4r₁. What is the ratio of their time periods T₁/T₂?

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