Kepler's Second Law
A comet travels around the Sun on a highly elongated elliptical orbit in which its farthest distance from the Sun is four times its closest distance. What is the ratio of the comet's speed at the closest point to its speed at the farthest point?
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About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- kepler's second law
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
4 : 1
Kepler's second law, the law of areas, states that the line joining a planet or comet to the Sun sweeps out equal areas in equal times, which is a direct consequence of the conservation of angular momentum because the Sun's gravity is a central force exerting no torque. Angular momentum at perihelion and aphelion gives mvprp=mvara, since the velocity is perpendicular to the radius at both turning points. Rearranging, vavp=rpra. With ra=4rp, the ratio becomes vavp=4, that is 4 : 1. The option 1 : 4 inverts the relationship, implying the comet moves slower when closest, which is physically wrong. The option 2 : 1 wrongly takes a square root of the distance ratio. The option 16 : 1 incorrectly squares the distance ratio. This is the NCERT angular-momentum interpretation of the law of areas. The deeper reason the law holds is that gravity is a central force, always directed along the line joining the comet to the Sun, so it produces no torque about the Sun and angular momentum L=mvr remains strictly constant throughout the orbit. The same conservation principle also explains why the comet sweeps equal areas in equal times, since the areal velocity dtdA=2mL is itself fixed. A plausibility check confirms the comet whips fastest near the Sun and crawls slowest far away, consistent with everyday observations of cometary motion.
This hard difficulty physics question is from the chapter gravitation, covering the topic of kepler's second law. It appeared in the 2025 exam.
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