Isothermal Process
Mediumchemistry
For an ideal gas undergoing isothermal expansion, which statement is correct?
Select the correct option:
Solution
Incorrect! Answer:
ΔU = 0, Q = W
In an Isothermal Process, the temperature (T) of the system remains constant.
- Internal Energy: For an ideal gas, U depends only on Temperature (U=f(T)). Therefore, ΔU=nCvΔT=0.
- First Law: ΔU=q−w (with work done by system conventionally w).
- 0=q−w⟹q=w.
- During isothermal expansion, the system absorbs heat (q) from the surroundings and converts it entirely into work (w) to keep the internal energy (and thus temperature) constant.
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About This Question
- Subject
- chemistry
- Chapter
- chemical thermodynamics
- Topic
- isothermal process
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
ΔU = 0, Q = W
In an Isothermal Process, the temperature (T) of the system remains constant.
- Internal Energy: For an ideal gas, U depends only on Temperature (U=f(T)). Therefore, ΔU=nCvΔT=0.
- First Law: ΔU=q−w (with work done by system conventionally w).
- 0=q−w⟹q=w.
- During isothermal expansion, the system absorbs heat (q) from the surroundings and converts it entirely into work (w) to keep the internal energy (and thus temperature) constant.
This medium difficulty chemistry question is from the chapter chemical thermodynamics, covering the topic of isothermal process. It appeared in the 2025 exam.
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