isothermal process

Question

For an ideal gas undergoing isothermal expansion, which statement is correct?

RankGuru · Accepted Answer

In an **Isothermal Process**, the temperature ($T$) of the system remains constant.
1. **Internal Energy**: For an ideal gas, $U$ depends only on Temperature ($U = f(T)$). Therefore, $\Delta U = n C_v \Delta T = 0$.
2. **First Law**: $\Delta U = q - w$ (with work done by system conventionally $w$). 
- $0 = q - w \implies q = w$.
- During isothermal expansion, the system absorbs heat ($q$) from the surroundings and converts it entirely into work ($w$) to keep the internal energy (and thus temperature) constant.

Rank Guru

isothermal process

Select the correct option: