Ionic Radius Vs Atomic Radius
Mediumchemistry
Which statement is correct regarding ionic vs atomic radius?
Select the correct option:
Solution
Incorrect! Answer:
For same element cation < atom < anion
- Cation Formation: Losing an electron increases the effective nuclear charge felt by remaining electrons and sometimes removes a whole valence shell. Result: Cation < Neutral Atom.
- Anion Formation: Adding an electron increases electron-electron repulsion, forcing the electron cloud to expand. Effective nuclear charge per electron decreases. Result: Anion > Neutral Atom.
- Combined Order: For a given element (e.g., Iodine), the size comparison is: Anion (I−) > Neutral (I) > Cation (I+).
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About This Question
- Subject
- chemistry
- Chapter
- classification of elements and periodicity in properties
- Topic
- ionic radius vs atomic radius
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
For same element cation < atom < anion
- Cation Formation: Losing an electron increases the effective nuclear charge felt by remaining electrons and sometimes removes a whole valence shell. Result: Cation < Neutral Atom.
- Anion Formation: Adding an electron increases electron-electron repulsion, forcing the electron cloud to expand. Effective nuclear charge per electron decreases. Result: Anion > Neutral Atom.
- Combined Order: For a given element (e.g., Iodine), the size comparison is: Anion (I−) > Neutral (I) > Cation (I+).
This medium difficulty chemistry question is from the chapter classification of elements and periodicity in properties, covering the topic of ionic radius vs atomic radius. It appeared in the 2025 exam.
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