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Ionic Equilibrium

Mediumchemistry

The solubility product (Ksp) of AgCl at 25°C is 1.8 × 10⁻¹⁰. The maximum concentration of Ag⁺ ions that can exist in a 0.01 M NaCl solution is:

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About This Question

Subject
chemistry
Chapter
equilibrium
Topic
ionic equilibrium
Difficulty
Medium
Year
2025
Tags
Solubility ProductCommon Ion EffectAgCl

Solution

Correct Answer:

1.8 × 10⁻⁸ mol L⁻¹

For AgCl, Ksp = [Ag⁺][Cl⁻] = 1.8 × 10⁻¹⁰. In a 0.01 M NaCl solution, [Cl⁻] ≈ 0.01 M (since NaCl dissociates completely and the contribution from AgCl dissolution is negligible). Therefore, [Ag⁺] = Ksp/[Cl⁻] = 1.8 × 10⁻¹⁰ / 0.01 = 1.8 × 10⁻⁸ mol L⁻¹. This demonstrates the common ion effect: the presence of Cl⁻ from NaCl suppresses the dissolution of AgCl, drastically reducing the Ag⁺ concentration compared to dissolution in pure water where [Ag⁺] would be √(1.8 × 10⁻¹⁰) = 1.34 × 10⁻⁵ mol L⁻¹.

This medium difficulty chemistry question is from the chapter equilibrium, covering the topic of ionic equilibrium. It appeared in the 2025 exam.

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