Ionic Bonding And Lattice Energy
The Born-Haber cycle for the formation of MgCl_2 from its elements involves five enthalpy terms; if the lattice energy of MgCl_2 is -2526 kJ/mol, the enthalpy of sublimation of Mg is +148 kJ/mol, first ionisation energy of Mg is +738 kJ/mol, second ionisation energy of Mg is +1451 kJ/mol, bond dissociation energy of Cl_2 is +244 kJ/mol, and electron affinity of Cl is -349 kJ/mol, what is the enthalpy of formation of MgCl_2 in kJ/mol?
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Solution
−642kJ/mol
The Born-Haber cycle applies Hess's law to ionic compound formation by summing all the enthalpy steps needed to go from elements in their standard states to the ionic lattice. For MgCl_2, the steps are: (1) Sublimation of Mg(s) to Mg(g): +148 kJ/mol. (2) First ionisation energy of Mg(g) to Mg^+(g): +738 kJ/mol. (3) Second ionisation energy of Mg^+(g) to Mg^{2+}(g): +1451 kJ/mol. (4) Dissociation of Cl_2(g) to 2 Cl(g): +244 kJ/mol (for one mole of Cl_2, producing 2 Cl atoms needed for 2 Cl^- ions). (5) Electron affinity for 2 Cl(g) to 2 Cl^-(g): 2 × (-349) = -698 kJ/mol. (6) Lattice energy for Mg^{2+}(g) + 2 Cl^-(g) to MgCl_2(s): -2526 kJ/mol. Enthalpy of formation = 148 + 738 + 1451 + 244 + (-698) + (-2526) = 148 + 738 + 1451 + 244 - 698 - 2526. Step by step: 148 + 738 = 886; 886 + 1451 = 2337; 2337 + 244 = 2581; 2581 - 698 = 1883; 1883 - 2526 = -643 kJ/mol ≈ -642 kJ/mol. Option +642 kJ/mol has the correct magnitude but wrong sign; formation of ionic compounds from elements is exothermic. Option -1263 kJ/mol doubles the lattice energy contribution incorrectly. Option +286 kJ/mol is not derivable from the given data. This is a standard NCERT Born-Haber calculation. Plausibility: the experimental enthalpy of formation of MgCl_2 is approximately -641 kJ/mol, matching the calculated value.
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About This Question
- Subject
- chemistry
- Chapter
- chemical bonding and molecular structure
- Topic
- ionic bonding and lattice energy
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
−642kJ/mol
The Born-Haber cycle applies Hess's law to ionic compound formation by summing all the enthalpy steps needed to go from elements in their standard states to the ionic lattice. For MgCl_2, the steps are: (1) Sublimation of Mg(s) to Mg(g): +148 kJ/mol. (2) First ionisation energy of Mg(g) to Mg^+(g): +738 kJ/mol. (3) Second ionisation energy of Mg^+(g) to Mg^{2+}(g): +1451 kJ/mol. (4) Dissociation of Cl_2(g) to 2 Cl(g): +244 kJ/mol (for one mole of Cl_2, producing 2 Cl atoms needed for 2 Cl^- ions). (5) Electron affinity for 2 Cl(g) to 2 Cl^-(g): 2 × (-349) = -698 kJ/mol. (6) Lattice energy for Mg^{2+}(g) + 2 Cl^-(g) to MgCl_2(s): -2526 kJ/mol. Enthalpy of formation = 148 + 738 + 1451 + 244 + (-698) + (-2526) = 148 + 738 + 1451 + 244 - 698 - 2526. Step by step: 148 + 738 = 886; 886 + 1451 = 2337; 2337 + 244 = 2581; 2581 - 698 = 1883; 1883 - 2526 = -643 kJ/mol ≈ -642 kJ/mol. Option +642 kJ/mol has the correct magnitude but wrong sign; formation of ionic compounds from elements is exothermic. Option -1263 kJ/mol doubles the lattice energy contribution incorrectly. Option +286 kJ/mol is not derivable from the given data. This is a standard NCERT Born-Haber calculation. Plausibility: the experimental enthalpy of formation of MgCl_2 is approximately -641 kJ/mol, matching the calculated value.
This hard difficulty chemistry question is from the chapter chemical bonding and molecular structure, covering the topic of ionic bonding and lattice energy. It appeared in the 2025 exam.
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