Inverse Of A Product
For two invertible square matrices A and B of the same order, the inverse of the product AB is correctly expressed by which of the following formulas?
Select the correct option:
Solution
B inverse times A inverse
The inverse of a product of invertible matrices reverses the order of the factors, the reversal law that JEE Advanced expects students to apply correctly. To verify, multiply AB by B^{-1}A^{-1}: (AB)(B^{-1}A^{-1}) = A(BB^{-1})A^{-1} = A·I·A^{-1} = AA^{-1} = I, and similarly the product in the other order is the identity. Hence (AB)^{-1} = B^{-1}A^{-1}. The order reversal is essential because matrix multiplication is non-commutative. Option A inverse times B inverse fails the verification, since (AB)(A^{-1}B^{-1}) does not simplify to the identity in general. Option A inverse plus B inverse confuses inversion with addition. Option (AB) inverse equals AB is false for non-involutory matrices. Hence (AB)^{-1} = B^{-1}A^{-1}. Plausibility check: the reversal mirrors the transpose law (AB)^T = B^T A^T, and the direct multiplication collapsing to the identity confirms B^{-1}A^{-1} is the correct inverse. The reversal law for inverses parallels the reversal law for transposes, both arising because undoing or transposing a composition reverses the order of its constituent operations. Internalizing this last-on-first-off ordering prevents a frequent algebraic error and is essential when manipulating chains of matrix products, where careless reordering silently produces an expression that is not actually the intended inverse.
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About This Question
- Subject
- mathematics
- Chapter
- matrices and determinants
- Topic
- inverse of a product
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
B inverse times A inverse
The inverse of a product of invertible matrices reverses the order of the factors, the reversal law that JEE Advanced expects students to apply correctly. To verify, multiply AB by B^{-1}A^{-1}: (AB)(B^{-1}A^{-1}) = A(BB^{-1})A^{-1} = A·I·A^{-1} = AA^{-1} = I, and similarly the product in the other order is the identity. Hence (AB)^{-1} = B^{-1}A^{-1}. The order reversal is essential because matrix multiplication is non-commutative. Option A inverse times B inverse fails the verification, since (AB)(A^{-1}B^{-1}) does not simplify to the identity in general. Option A inverse plus B inverse confuses inversion with addition. Option (AB) inverse equals AB is false for non-involutory matrices. Hence (AB)^{-1} = B^{-1}A^{-1}. Plausibility check: the reversal mirrors the transpose law (AB)^T = B^T A^T, and the direct multiplication collapsing to the identity confirms B^{-1}A^{-1} is the correct inverse. The reversal law for inverses parallels the reversal law for transposes, both arising because undoing or transposing a composition reverses the order of its constituent operations. Internalizing this last-on-first-off ordering prevents a frequent algebraic error and is essential when manipulating chains of matrix products, where careless reordering silently produces an expression that is not actually the intended inverse.
This easy difficulty mathematics question is from the chapter matrices and determinants, covering the topic of inverse of a product. It appeared in the 2025 exam.
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