Integration By Parts
Determine the indefinite integral of x times e raised to the power x using the standard integration-by-parts framework with the appropriate ILATE ordering.
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About This Question
- Subject
- mathematics
- Chapter
- integral calculus
- Topic
- integration by parts
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
(x−1)ex+C
Integration by parts applies whenever a product of dissimilar function types appears in the integrand; here the algebraic factor x meets the exponential factor e^x, two functions that no single substitution can simplify together. The method is the reverse of the product rule for differentiation, trading a hard integral for an easier remaining one. The ILATE ordering chooses u = x as the algebraic part and dv = e^x,dx as the exponential part, because algebraic functions precede exponential ones in differentiation priority. Then du = dx and v = e^x. Applying the formula \int u,dv = uv - \int v,du gives x e^x - \int e^x,dx = x e^x - e^x + C = (x-1)e^x + C. The key insight is that differentiating x removes it entirely, leaving a clean exponential to integrate. Option (x+1)e^x results from a sign error when subtracting the remaining integral. Option x e^x stops prematurely without integrating the leftover term. Option x^2 e^x/2 wrongly treats e^x as a constant and integrates x as a simple power. As a final plausibility check, differentiating (x-1)e^x by the product rule gives e^x + (x-1)e^x = x e^x, which is exactly the integrand, confirming the antiderivative holds over all real x.
This easy difficulty mathematics question is from the chapter integral calculus, covering the topic of integration by parts. It appeared in the 2025 exam.
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