Instrument Use (screw Gauge)
Easyphysics
Pitch of a screw gauge is 0.5 mm and circular scale has 50 divisions. Least count is:
Select the correct option:
Solution
Incorrect! Answer:
0.01 mm
The Least Count (LC) of a Screw Gauge is defined as: LC=Total number of divisions on circular scalePitch Given:
- Pitch = 0.5 mm
- Divisions = 50 LC=500.5 mm=0.01 mm.
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About This Question
- Subject
- physics
- Chapter
- physics and measurement
- Topic
- instrument use (screw gauge)
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.01 mm
The Least Count (LC) of a Screw Gauge is defined as: LC=Total number of divisions on circular scalePitch Given:
- Pitch = 0.5 mm
- Divisions = 50 LC=500.5 mm=0.01 mm.
This easy difficulty physics question is from the chapter physics and measurement, covering the topic of instrument use (screw gauge). It appeared in the 2025 exam.
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