Indefinite Integrals
Evaluate ∫ex(x1+xlnx)dx (Assume x>0 and base e for ln).
Select the correct option:
Solution
exlnx+C
-
Simplify the integrand: x1+xlnx=x1+lnx.
-
Recognize the standard form ∫ex(f(x)+f′(x))dx=exf(x). Let f(x)=lnx. Then f′(x)=1/x.
-
The integral becomes: ∫ex(lnx+x1)dx=exlnx+C.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More indefinite integrals Practice Questions
Find the indefinite integral of the function 1 divided by the product x times the natural logarithm ...
Find the indefinite integral of the function 1 divided by the product x times the natural logarithm ...
The integral ∫sin(x) dx equals
The integral ∫sin(x) dx equals
The integral ∫(1/x) dx equals
The integral ∫(1/x) dx equals
The integral ∫x² dx equals
The integral ∫x² dx equals
The integral ∫eˣ dx equals
The integral ∫eˣ dx equals
About This Question
- Subject
- mathematics
- Chapter
- integral calculus
- Topic
- indefinite integrals
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
exlnx+C
-
Simplify the integrand: x1+xlnx=x1+lnx.
-
Recognize the standard form ∫ex(f(x)+f′(x))dx=exf(x). Let f(x)=lnx. Then f′(x)=1/x.
-
The integral becomes: ∫ex(lnx+x1)dx=exlnx+C.
This easy difficulty mathematics question is from the chapter integral calculus, covering the topic of indefinite integrals. It appeared in the 2025 exam.
Looking for more practice? Explore all mathematics questions or browse integral calculus questions on RankGuru.