Impulse And Momentum
Ball of mass 0.2 kg moving at 30 m/s is stopped in 0.05 s. Average force is:
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About This Question
- Subject
- physics
- Chapter
- laws of motion
- Topic
- impulse and momentum
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
120 N
Using the Impulse-Momentum Theorem: Impulse=FavgΔt=Δp=mvf−mvi Given:
- m=0.2 kg
- vi=30 m/s
- vf=0 (stopped)
- Δt=0.05 s Calculation: ∣Δp∣=m∣vf−vi∣=0.2×30=6 kg m/s. Favg=ΔtΔp=0.056=120 N.
This easy difficulty physics question is from the chapter laws of motion, covering the topic of impulse and momentum. It appeared in the 2025 exam.
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