impulse and momentum

Question

Ball of mass 0.2 kg moving at 30 m/s is stopped in 0.05 s. Average force is:

RankGuru · Accepted Answer

Using the Impulse-Momentum Theorem:
$	ext{Impulse} = \vec{F}_{avg} \Delta t = \Delta \vec{p} = m \vec{v}_f - m \vec{v}_i$
Given:
- $m = 0.2 	ext{ kg}$
- $v_i = 30 	ext{ m/s}$
- $v_f = 0 	ext{ (stopped)}$
- $\Delta t = 0.05 	ext{ s}$
Calculation:
$|\Delta p| = m |v_f - v_i| = 0.2 	imes 30 = 6 	ext{ kg m/s}$.
$F_{avg} = \frac{\Delta p}{\Delta t} = \frac{6}{0.05} = 120 	ext{ N}$.

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