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Hydrogen Spectrum - Balmer Series

Mediumphysics

When the electron in a hydrogen atom drops from the third energy level to the second energy level, a visible red photon is emitted. What is the wavelength of this spectral line, taking the Rydberg constant as 1.097 × 10^7 per metre?

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About This Question

Subject
physics
Chapter
atoms and nuclei
Topic
hydrogen spectrum - balmer series
Difficulty
Medium
Year
2025
Tags
Balmer seriesRydberg formulahydrogen spectrumH-alpha linephoton emission

Solution

Correct Answer:

656 nm

Spectral wavelengths in hydrogen follow the Rydberg relation , and a transition ending at belongs to the visible Balmer series. For the jump (the H-alpha line), . Hence m nm. The value 486 nm is the H-beta line (), not the requested transition. The value 121 nm is the Lyman-alpha line (), which lies in the ultraviolet, not the visible. The value 365 nm is the Balmer series limit (). The Balmer series, lying in the visible region, was historically the first hydrogen series discovered and gave early support to the Bohr model. Because the lower level is fixed at , the longest-wavelength line of the series arises from the smallest energy gap, namely the transition. This matches the NCERT Balmer-series description. A plausibility check confirms 656 nm falls in the red part of the visible spectrum, exactly where H-alpha is observed experimentally.

This medium difficulty physics question is from the chapter atoms and nuclei, covering the topic of hydrogen spectrum - balmer series. It appeared in the 2025 exam.

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