Hofmann Bromamide
Mediumchemistry
Hofmann bromamide reaction converts an amide to:
Select the correct option:
Solution
Incorrect! Answer:
Primary amine with one fewer carbon
- Reactants: Amide (R−CONH2) treated with Bromine (Br2) and aqueous/alcoholic KOH/NaOH.
- Transformation: R−CONH2+Br2+4NaOH→R−NH2+Na2CO3+2NaBr+2H2O.
- Mechanism Key: The reaction involves the migration of the alkyl group from the carbonyl carbon to the Nitrogen atom (Hofmann rearrangement).
- Carbon Count: The carbonyl Carbon (C=O) is lost as Carbonate (CO32−).
- Result: The product is a primary amine which has one carbon atom less than the starting amide. This is a powerful method for descending a series.
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About This Question
- Subject
- chemistry
- Chapter
- nitrogen organics
- Topic
- hofmann bromamide
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Primary amine with one fewer carbon
- Reactants: Amide (R−CONH2) treated with Bromine (Br2) and aqueous/alcoholic KOH/NaOH.
- Transformation: R−CONH2+Br2+4NaOH→R−NH2+Na2CO3+2NaBr+2H2O.
- Mechanism Key: The reaction involves the migration of the alkyl group from the carbonyl carbon to the Nitrogen atom (Hofmann rearrangement).
- Carbon Count: The carbonyl Carbon (C=O) is lost as Carbonate (CO32−).
- Result: The product is a primary amine which has one carbon atom less than the starting amide. This is a powerful method for descending a series.
This medium difficulty chemistry question is from the chapter nitrogen organics, covering the topic of hofmann bromamide. It appeared in the 2025 exam.
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