hinsberg test

Question

In Hinsberg test, secondary amine gives product that is:

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1. **The Reagent**: Benzenesulfonyl chloride ($C_6H_5SO_2Cl$).
2. **Primary Amine ($1^\circ$)**: Forms a sulfonamide with a remaining $H$ on the Nitrogen ($R-NH-SO_2Ph$). This Hydrogen is acidic and reacts with $NaOH$ to form a salt, making it **soluble**.
3. **Secondary Amine ($2^\circ$)**: Forms a sulfonamide with NO remaining $H$ atoms on the Nitrogen ($R_2N-SO_2Ph$). Since there is no acidic proton, it cannot react with $NaOH$.
4. **Observation**: The product is formed but remains **insoluble** in the alkaline medium.
5. **Tertiary Amine ($3^\circ$)**: Does not react at all with the reagent.

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hinsberg test

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More hinsberg test Practice Questions

Hinsberg reagent (benzenesulfonyl chloride) is used to distinguish: