High Vs Low Spin
[Fe(H2O)6]2+ vs [Fe(CN)6]4−: Which statement is correct?
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About This Question
- Subject
- chemistry
- Chapter
- coordination compounds
- Topic
- high vs low spin
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
[Fe(H2O)6]2+ high spin, [Fe(CN)6]4− low spin
- Metal Center: Both complexes contain Fe2+ with a d6 electronic configuration.
- Spectrochemical Series: Ligands vary in their ability to split the d-orbitals (Crystal Field Splitting Energy, Δo).
- Analysis of [Fe(H2O)6]2+:
- Water (H2O) is a weak field ligand. Δo<PairingEnergy(P).
- Electrons do not pair up; they occupy both t2g and eg levels (t2g4eg2).
- Presence of 4 unpaired electrons ⟹ High Spin.
- Analysis of [Fe(CN)6]4−:
- Cyanide (CN−) is a strong field ligand. Δo>P.
- Electrons prefer to pair up in the lower t2g orbitals (t2g6).
- Zero unpaired electrons ⟹ Low Spin.
This medium difficulty chemistry question is from the chapter coordination compounds, covering the topic of high vs low spin. It appeared in the 2025 exam.
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