Helical Path And Pitch
A charged particle enters a uniform magnetic field at an angle to the field lines, so its velocity has components both along and across the field. Which statement correctly explains why the resulting trajectory is a helix rather than a simple circle?
Select the correct option:
Solution
The parallel velocity component is unaffected while the perpendicular component drives circular motion
When a charge enters a uniform field at an angle θ, its velocity is resolved into a component v∥=vcosθ along the field and v⊥=vsinθ across it. The magnetic force qv×B involves only the perpendicular component, because the parallel component is antiparallel or parallel to B and contributes nothing to the cross product. Hence v∥ remains constant, carrying the particle steadily along the field, while v⊥ produces uniform circular motion of radius r=qBmv⊥. The superposition of steady forward drift and circular motion is a helix, whose pitch is p=v∥T=qB2πmvcosθ. The option claiming the force changes the parallel component is wrong, since the force is perpendicular to velocity. The option that both components shrink contradicts the fact that magnetic force does no work and cannot change speed. The option swapping the roles of the components is geometrically incorrect. NCERT presents this helical motion explicitly. A check confirms that at θ=90∘ the pitch vanishes, recovering pure circular motion. Helical motion appears throughout nature and technology: charged particles from the Sun spiral along the Earth's magnetic field lines toward the poles, producing the auroras, and the same principle guides beams in mass spectrometers and confines plasma in magnetic-bottle devices. The pitch shrinks as the entry angle approaches ninety degrees and grows as it approaches zero, smoothly interpolating between a tight circle and an almost straight drift along the field.
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About This Question
- Subject
- physics
- Chapter
- magnetic effects of current and magnetism
- Topic
- helical path and pitch
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
The parallel velocity component is unaffected while the perpendicular component drives circular motion
When a charge enters a uniform field at an angle θ, its velocity is resolved into a component v∥=vcosθ along the field and v⊥=vsinθ across it. The magnetic force qv×B involves only the perpendicular component, because the parallel component is antiparallel or parallel to B and contributes nothing to the cross product. Hence v∥ remains constant, carrying the particle steadily along the field, while v⊥ produces uniform circular motion of radius r=qBmv⊥. The superposition of steady forward drift and circular motion is a helix, whose pitch is p=v∥T=qB2πmvcosθ. The option claiming the force changes the parallel component is wrong, since the force is perpendicular to velocity. The option that both components shrink contradicts the fact that magnetic force does no work and cannot change speed. The option swapping the roles of the components is geometrically incorrect. NCERT presents this helical motion explicitly. A check confirms that at θ=90∘ the pitch vanishes, recovering pure circular motion. Helical motion appears throughout nature and technology: charged particles from the Sun spiral along the Earth's magnetic field lines toward the poles, producing the auroras, and the same principle guides beams in mass spectrometers and confines plasma in magnetic-bottle devices. The pitch shrinks as the entry angle approaches ninety degrees and grows as it approaches zero, smoothly interpolating between a tight circle and an almost straight drift along the field.
This hard difficulty physics question is from the chapter magnetic effects of current and magnetism, covering the topic of helical path and pitch. It appeared in the 2025 exam.
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