Heat Capacity
A 50.0 g sample of water is heated from 25.0°C to 45.0°C. (Specific heat of water = 4.18 J g⁻¹ K⁻¹). Heat absorbed (q) is:
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About This Question
- Subject
- chemistry
- Chapter
- chemical thermodynamics
- Topic
- heat capacity
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
4180 J
- Formula: The heat absorbed or released during a temperature change is given by q=m⋅c⋅ΔT.
- Variables:
- Mass (m) = 50.0 g.
- Specific heat capacity (c) = 4.18 J g−1 K−1.
- Temperature change (ΔT) = Tfinal−Tinitial=45.0−25.0=20.0∘C (or 20.0 K).
- Calculation:
- q=50.0×4.18×20.0
- q=1000×4.18/1
- q=4180 J.
- Result: The energy absorbed by the water is 4180 J.
This medium difficulty chemistry question is from the chapter chemical thermodynamics, covering the topic of heat capacity. It appeared in the 2025 exam.
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