Hardy-weinberg Principle

Question

In a population of 1000 individuals, 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is:

RankGuru · Accepted Answer

1. **Total Population**: $1000$ individuals, so total alleles = $2000$.
2. **Count Allele A**: 
   - From $AA$ (360 individuals): $360 	imes 2 = 720$ alleles.
   - From $Aa$ (480 individuals): $480 	imes 1 = 480$ alleles.
   - Total A alleles = $720 + 480 = 1200$.
3. **Frequency Calculation**: $p = \frac{	ext{Total A}}{	ext{Total alleles}} = \frac{1200}{2000} = 0.6$.
4. **Hardy-Weinberg check**: $p^2 = (0.6)^2 = 0.36$, which matches the $AA$ frequency ($360/1000$).

Hardy-weinberg Principle

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