Hardy-weinberg Principle
Hardbiology
In a population of 1000 individuals, 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is:
Select the correct option:
Solution
Incorrect! Answer:
0.6
- Total Population: 1000 individuals, so total alleles = 2000.
- Count Allele A:
- From AA (360 individuals): 360×2=720 alleles.
- From Aa (480 individuals): 480×1=480 alleles.
- Total A alleles = 720+480=1200.
- Frequency Calculation: p=Total allelesTotal A=20001200=0.6.
- Hardy-Weinberg check: p2=(0.6)2=0.36, which matches the AA frequency (360/1000).
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About This Question
- Subject
- biology
- Chapter
- evolution
- Topic
- hardy-weinberg principle
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
0.6
- Total Population: 1000 individuals, so total alleles = 2000.
- Count Allele A:
- From AA (360 individuals): 360×2=720 alleles.
- From Aa (480 individuals): 480×1=480 alleles.
- Total A alleles = 720+480=1200.
- Frequency Calculation: p=Total allelesTotal A=20001200=0.6.
- Hardy-Weinberg check: p2=(0.6)2=0.36, which matches the AA frequency (360/1000).
This hard difficulty biology question is from the chapter evolution, covering the topic of hardy-weinberg principle. It appeared in the 2025 exam.
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