Halogenation Of Alkanes

Initiation: Homolytic fission of $C l_{2}$ to generate $C l^{.}$ radicals.
Propagation: $C l^{.}$ reacts with methane to form methyl radical ( $C H_{3}^{.}$ ) and $H Cl$ . Then $C H_{3}^{.}$ reacts with $C l_{2}$ to form $C H_{3} Cl$ and regenerate $C l^{.}$ .
Termination: Collision of any two radicals stops the chain.

Since an $H$ atom is substituted by a $Cl$ atom, it is a substitution reaction.

This easy difficulty chemistry question is from the chapter hydrocarbons, covering the topic of halogenation of alkanes. It appeared in the 2025 exam.

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Halogenation Of Alkanes

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