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Grouping And Division

Hardmathematics

The number of ways to divide 12 distinct books into three groups containing 4, 4 and 4 books respectively, where the groups are unlabelled and indistinguishable, equals which value?

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About This Question

Subject
mathematics
Chapter
permutations and combinations
Topic
grouping and division
Difficulty
Hard
Year
2025
Tags
advanced-calculus-drillgroupingmultinomialunlabelled-groupsdivision-of-objects

Solution

Correct Answer:

Dividing distinct objects into equal unlabelled groups requires dividing the labelled count by the factorial of the number of equal groups, a subtle JEE Advanced correction. The number of ways to split 12 books into ordered groups of 4, 4 and 4 is the multinomial 12!/(4!·4!·4!) = 34650. Since the three groups are of equal size and unlabelled, each distinct division has been counted 3! = 6 times by permuting the identical-sized groups. Dividing by 6 gives 34650/6 = 5775. Option 34650 is the labelled count, not the unlabelled one. Option 1925 divides by an incorrect factor. Option 11550 divides by only 3 instead of 3!. Hence there are 5775 ways. Plausibility check: the correction factor must equal the number of ways to permute the equal groups, which is 3! = 6, and 34650/6 = 5775 confirms that swapping identical-sized groups does not create new divisions. Stars and bars is the definitive tool for distributing identical objects into distinct groups, and the at-least-one condition is dispatched by reserving the minimum allotment before applying the free-distribution count. The method counts non-negative integer solutions of a linear equation by arranging dividers among identical items, a translation that turns many word problems into a single binomial coefficient.

This hard difficulty mathematics question is from the chapter permutations and combinations, covering the topic of grouping and division. It appeared in the 2025 exam.

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