Greatest Value Of Modulus Sum
Among all complex numbers z lying on the circle defined by |z| = 1, the maximum value attained by the expression |z^2 - z + 1| over this unit circle equals which number?
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About This Question
- Subject
- mathematics
- Chapter
- complex numbers and quadratic equations
- Topic
- greatest value of modulus sum
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
3
Maximizing the modulus of a polynomial in z on the unit circle is a JEE Advanced extremal problem best handled by writing z = e^{iθ} and reducing to a real trigonometric function. On |z| = 1 we have z·z-bar = 1, so z-bar = 1/z. Consider |z^2 - z + 1|. Factor out z: z^2 - z + 1 = z(z + 1/z - 1) = z((z + z-bar) - 1) since 1/z = z-bar on the unit circle. With z + z-bar = 2cosθ, the bracket becomes (2cosθ - 1), a real number, and |z| = 1, so |z^2 - z + 1| = |2cosθ - 1|. As θ varies, 2cosθ ranges over [-2, 2], so 2cosθ - 1 ranges over [-3, 1], whose maximum absolute value is 3, achieved at cosθ = -1, that is z = -1. Option 1 takes only the upper end of the bracket. Option 2 ignores the constant shift. Option 13/4 confuses this with a different extremum. Hence the maximum is 3. Plausibility check: at z = -1, z^2 - z + 1 = 1 + 1 + 1 = 3, directly attaining the bound and confirming the trigonometric reduction.
This hard difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of greatest value of modulus sum. It appeared in the 2025 exam.
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