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Greatest Term

Mediummathematics

For the numerical expansion of (1 + x)^{n} with specific values applied, the greatest term is identified through the ratio of consecutive terms; which inequality governs the index of that greatest term?

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About This Question

Subject
mathematics
Chapter
binomial theorem and its simple applications
Topic
greatest term
Difficulty
Medium
Year
2025
Tags
advanced-calculus-drillgreatest-termconsecutive-ratiounimodalityterm-optimisation

Solution

Correct Answer:

The greatest term in a numerical binomial expansion is located by examining the ratio of a term to its predecessor and finding where this ratio stops exceeding one, a classic JEE Advanced optimisation idea. For (1 + x)^n the ratio is T_{r+1}/T_r = [C(n, r)/C(n, r-1)] x = [(n - r + 1)/r] x. The terms increase as long as this ratio is at least one, that is while T_{r+1}/T_r >= 1, and they start decreasing once the ratio drops below one; the greatest term occurs at the last r for which the ratio is still greater than or equal to one. Hence the governing condition is T_{r+1}/T_r >= 1. Option T_{r+1}/T_r = n has no general validity and confuses the ratio with the exponent. Option T_{r+1} - T_r = 0 always is false because terms genuinely change in size. Option T_{r+1}/T_r <= 0 is impossible for positive terms. The transition of the ratio through one marks the peak. Plausibility check: since the ratio decreases steadily in r, there is a unique crossover, guaranteeing a well-defined greatest term, consistent with the unimodal nature of the expansion.

This medium difficulty mathematics question is from the chapter binomial theorem and its simple applications, covering the topic of greatest term. It appeared in the 2025 exam.

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