Gravitational Field Intensity
Two identical point masses are fixed at the two ends of a straight rod and a test particle is placed exactly at the midpoint between them. What is the resultant gravitational field intensity experienced by the test particle at that midpoint?
Select the correct option:
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More gravitation Practice Questions
At a point located at a distance of 2R from the centre of a uniform spherical planet of radius R, th...
At a point located at a distance of 2R from the centre of a uniform spherical planet of radius R, th...
The gravitational field intensity at a point is 5 N/kg. What force will a 2 kg mass experience at th...
The gravitational field intensity at a point is 5 N/kg. What force will a 2 kg mass experience at th...
The universal gravitational constant G is described as a fundamental constant of nature in the study...
The universal gravitational constant G is described as a fundamental constant of nature in the study...
Two particles of mass m and 4m are fixed at a separation d on a frictionless table. At what distance...
Two particles of mass m and 4m are fixed at a separation d on a frictionless table. At what distance...
A television broadcasting satellite must remain fixed above one point on the equator throughout the ...
A television broadcasting satellite must remain fixed above one point on the equator throughout the ...
An astronaut inside a spacecraft orbiting the Earth at constant speed feels completely weightless, e...
An astronaut inside a spacecraft orbiting the Earth at constant speed feels completely weightless, e...
A satellite of mass m revolves around the Earth of mass M in a stable circular orbit of radius r. Wh...
A satellite of mass m revolves around the Earth of mass M in a stable circular orbit of radius r. Wh...
Because the Earth rotates about its axis, the measured acceleration due to gravity for a stationary ...
Because the Earth rotates about its axis, the measured acceleration due to gravity for a stationary ...
A newly discovered asteroid orbits the Sun at a mean distance four times that of the Earth from the ...
A newly discovered asteroid orbits the Sun at a mean distance four times that of the Earth from the ...
According to Kepler's second law, a planet sweeps out equal areas in equal times as it moves around ...
According to Kepler's second law, a planet sweeps out equal areas in equal times as it moves around ...
A 500 kg payload is carried by rocket from the Earth's surface to a great height where it is effecti...
A 500 kg payload is carried by rocket from the Earth's surface to a great height where it is effecti...
At a certain point in space the gravitational potential due to a point mass is found to be negative ...
At a certain point in space the gravitational potential due to a point mass is found to be negative ...
About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- gravitational field intensity
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Zero
Gravitational field intensity is the force per unit mass produced by a source mass, given by E=r2GM and directed toward the source. It is a vector quantity, so contributions from several masses must be added as vectors, not as plain numbers. At the midpoint between two identical masses, each mass is at the same distance and produces a field of equal magnitude, but the two fields point in exactly opposite directions toward their respective masses. Their vector sum is therefore Enet=E−E=0. The option claiming twice the single-mass field wrongly adds the magnitudes as if both pointed the same way. The option equal to one mass ignores the second source entirely. The option infinite would only apply at the location of a point mass itself, not at the midpoint. This illustrates the NCERT principle of superposition for gravitational fields, which states that the total field at any point is the vector sum of the individual fields from each source mass acting independently. It is worth noting that although the net field, and hence the net force on a test particle, is zero at the midpoint, the gravitational potential there is not zero; potential is a scalar and the two negative contributions add rather than cancel. This distinction between a vanishing vector field and a non-zero scalar potential is a frequently tested subtlety. A sanity check confirms that by symmetry no preferred direction exists, so the net field must vanish.
This medium difficulty physics question is from the chapter gravitation, covering the topic of gravitational field intensity. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse gravitation questions on RankGuru.