Geostationary Satellite
What is the approximate height of a geostationary satellite above Earth's surface? (R = 6400 km, T = 24 hours, g = 10 m/s²)
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About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- geostationary satellite
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
36000 km
- Orbital Condition: A geostationary satellite must stay over the same spot, meaning its period T=24 hours (86,400 s).
- Radius Calculation: From T=2πGMr3:
- r=(4π2gR2T2)1/3.
- Constants Applied: r≈4.22×107 m or 42,200 km from the center.
- Height from Surface: h=r−REarth.
- Final Computation: 42,200−6,400≈35,800 km. The standard value used is 36,000 km.
This hard difficulty physics question is from the chapter gravitation, covering the topic of geostationary satellite. It appeared in the 2025 exam.
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