Geometric Progression

Easymathematics

The 5th term of a GP with first term 2 and common ratio 3 is

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162

486

1458

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Subject: mathematics
Chapter: sequence and series
Topic: geometric progression
Difficulty: Easy
Year: 2025

Solution

Correct Answer:

162

Identify GP Data: $a = 2, r = 3$ .
nth Term Formula: $T_{n} = a \cdot r^{n - 1}$ .
Calculation for $n = 5$ :
- $T_{5} = 2 \cdot 3^{5 - 1}$
- $T_{5} = 2 \cdot 3^{4}$
Computation:
- $2 \cdot 81 = 162$ .
Result: 162.

This easy difficulty mathematics question is from the chapter sequence and series, covering the topic of geometric progression. It appeared in the 2025 exam.

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Geometric Progression

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