Functions
If f(x) = (1 - x)/(1 + x), then f(f(x)) equals
Select the correct option:
Solution
x
- Composition: Substitute the entire expression back into itself.
- f(f(x))=1+(1+x1βxβ)1β(1+x1βxβ)β
- Simplify Numerator and Denominator:
- Numerator: 1+x(1+x)β(1βx)β=1+x2xβ
- Denominator: 1+x(1+x)+(1βx)β=1+x2β
- Final Ratio: 2/(1+x)2x/(1+x)β=x.
- Conclusion: The function is its own inverse (fβf=I), also known as an involutory function.
π Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More functions Practice Questions
Given f(x)=x1/x for x>0. The maximum value of f(x) is:
Given f(x)=x1/x for x>0. The maximum value of f(x) is:
The range of cosβ»ΒΉ(x) is
The range of cosβ»ΒΉ(x) is
The range of sinβ»ΒΉ(x) is
The range of sinβ»ΒΉ(x) is
The number of onto functions from a set A containing m elements to a set B containing n elements (m ...
The number of onto functions from a set A containing m elements to a set B containing n elements (m ...
If f: [0, β) β [0, β) is defined by f(x) = x/(1 + x), then f is
If f: [0, β) β [0, β) is defined by f(x) = x/(1 + x), then f is
If f: R β R is defined by f(x) = 2x + 3 and g: R β R is defined by g(x) = xΒ² + 1, then (gof)β»ΒΉ(10) e...
If f: R β R is defined by f(x) = 2x + 3 and g: R β R is defined by g(x) = xΒ² + 1, then (gof)β»ΒΉ(10) e...
About This Question
- Subject
- mathematics
- Chapter
- sets, relations and functions
- Topic
- functions
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
x
- Composition: Substitute the entire expression back into itself.
- f(f(x))=1+(1+x1βxβ)1β(1+x1βxβ)β
- Simplify Numerator and Denominator:
- Numerator: 1+x(1+x)β(1βx)β=1+x2xβ
- Denominator: 1+x(1+x)+(1βx)β=1+x2β
- Final Ratio: 2/(1+x)2x/(1+x)β=x.
- Conclusion: The function is its own inverse (fβf=I), also known as an involutory function.
This medium difficulty mathematics question is from the chapter sets, relations and functions, covering the topic of functions. It appeared in the 2025 exam.
Looking for more practice? Explore all mathematics questions or browse sets, relations and functions questions on RankGuru.