Functions
If f: [0, ∞) → [0, ∞) is defined by f(x) = x/(1 + x), then f is
Select the correct option:
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More sets, relations and functions Practice Questions
Given f(x)=x1/x for x>0. The maximum value of f(x) is:
Given f(x)=x1/x for x>0. The maximum value of f(x) is:
If f: R → R is defined by f(x) = 2x + 3 and g: R → R is defined by g(x) = x² + 1, then (gof)⁻¹(10) e...
If f: R → R is defined by f(x) = 2x + 3 and g: R → R is defined by g(x) = x² + 1, then (gof)⁻¹(10) e...
A function f: R → R is defined by f(x) = ax + b. If f(1) = 5 and f(3) = 13, then f(5) equals
A function f: R → R is defined by f(x) = ax + b. If f(1) = 5 and f(3) = 13, then f(5) equals
The number of onto functions from a set A containing m elements to a set B containing n elements (m ...
The number of onto functions from a set A containing m elements to a set B containing n elements (m ...
If f(x) = x/(x² + 1), then the range of f is
If f(x) = x/(x² + 1), then the range of f is
If f(x) = (1 - x)/(1 + x), then f(f(x)) equals
If f(x) = (1 - x)/(1 + x), then f(f(x)) equals
If f(x) = log(1 + x)/(1 - x), then f(2x/(1 + x²)) equals
If f(x) = log(1 + x)/(1 - x), then f(2x/(1 + x²)) equals
The domain of the function f(x) = √(9 - x²) is
The domain of the function f(x) = √(9 - x²) is
The function f(x) = |x| - x is
The function f(x) = |x| - x is
If f: [0, 1] → R is defined by f(x) = x³ - 6x² + 11x - 6 and g denotes the inverse of f on its range...
If f: [0, 1] → R is defined by f(x) = x³ - 6x² + 11x - 6 and g denotes the inverse of f on its range...
The period of the function f(x) = sin(4x) + cos(3x) is
The period of the function f(x) = sin(4x) + cos(3x) is
The function f: R → R defined by f(x) = x³ + 5 is
The function f: R → R defined by f(x) = x³ + 5 is
About This Question
- Subject
- mathematics
- Chapter
- sets, relations and functions
- Topic
- functions
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
One-one but not onto
- One-one (Injection): f′(x)=(1+x)2(1+x)−x=(1+x)21. Since the derivative is strictly positive for x∈[0,∞), the function is strictly increasing and thus one-one.
- Range Analysis: As x→∞, f(x)→xx=1. Since x is always positive, f(x) is always less than 1. Thus, Range =[0,1).
- Onto (Surjection): The codomain is provided as [0,∞). Since the range ([0,1)) is a proper subset of the codomain, the function is not onto.
- Conclusion: One-one but not onto.
This medium difficulty mathematics question is from the chapter sets, relations and functions, covering the topic of functions. It appeared in the 2025 exam.
Looking for more practice? Explore all mathematics questions or browse sets, relations and functions questions on RankGuru.