Functional Equations
A function f from positive reals to reals satisfies f(xy) = f(x) + f(y) for all positive x, y, and f(2) = 3; the value of f(32) is which number?
Select the correct option:
Solution
15
The Cauchy-type relation f(xy) = f(x) + f(y) characterizes logarithm-like functions and is a recurring JEE Advanced functional-equation pattern. Setting y = x gives f(x^2) = 2f(x), and more generally f(x^n) = n f(x) by induction. Since 32 = 2^5, we get f(32) = f(2^5) = 5 f(2) = 5·3 = 15. The additive-to-multiplicative structure means f behaves like a constant multiple of a logarithm base 2. Option 10 uses 2^5 incorrectly as 5·2. Option 12 applies the wrong exponent of 4. Option 96 mistakenly multiplies 32 by 3 as though f were linear in its argument. Hence f(32) = 15. Plausibility check: f(4) = 2f(2) = 6 and f(8) = 3f(2) = 9 follow the same rule, and f(32) = f(8)·? no—f(8·4)=f(8)+f(4)=9+6=15, independently confirming the value through a different factorization of 32. Cauchy-type functional equations characterize logarithms, exponentials, additive or linear maps depending on which operation pairing they encode, and the multiplicative-to-additive form here is the logarithmic signature. The pivotal step is anchoring the entire family of values to a single known input, here f of two, after which induction propagates that seed to every power, making the whole structure determinate from one datum and the rule.
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About This Question
- Subject
- mathematics
- Chapter
- sets, relations and functions
- Topic
- functional equations
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
15
The Cauchy-type relation f(xy) = f(x) + f(y) characterizes logarithm-like functions and is a recurring JEE Advanced functional-equation pattern. Setting y = x gives f(x^2) = 2f(x), and more generally f(x^n) = n f(x) by induction. Since 32 = 2^5, we get f(32) = f(2^5) = 5 f(2) = 5·3 = 15. The additive-to-multiplicative structure means f behaves like a constant multiple of a logarithm base 2. Option 10 uses 2^5 incorrectly as 5·2. Option 12 applies the wrong exponent of 4. Option 96 mistakenly multiplies 32 by 3 as though f were linear in its argument. Hence f(32) = 15. Plausibility check: f(4) = 2f(2) = 6 and f(8) = 3f(2) = 9 follow the same rule, and f(32) = f(8)·? no—f(8·4)=f(8)+f(4)=9+6=15, independently confirming the value through a different factorization of 32. Cauchy-type functional equations characterize logarithms, exponentials, additive or linear maps depending on which operation pairing they encode, and the multiplicative-to-additive form here is the logarithmic signature. The pivotal step is anchoring the entire family of values to a single known input, here f of two, after which induction propagates that seed to every power, making the whole structure determinate from one datum and the rule.
This medium difficulty mathematics question is from the chapter sets, relations and functions, covering the topic of functional equations. It appeared in the 2025 exam.
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