Friction

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A block of mass 10 kg is placed on a rough horizontal surface having a coefficient of friction µ = 0.5. If a horizontal force of 100 N is applied on it, then the acceleration of the block will be (g = 10 m/s^2):

RankGuru · Accepted Answer

1. **Limiting Friction ($f_l$)**: $f_l = \mu N = \mu mg = 0.5 	imes 10 	imes 10 = 50	ext{ N}$.
2. **Analysis**: The applied force $F_{applied} = 100	ext{ N}$ is greater than the limiting friction ($50	ext{ N}$), so the block will move.
3. **Net Force**: $F_{net} = F_{applied} - f_l = 100 - 50 = 50	ext{ N}$.
4. **Acceleration ($a$)**: $a = \frac{F_{net}}{m} = \frac{50}{10} = 5	ext{ m/s}^2$.

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