Free Fall
Easyphysics
If the value of g at Earth's surface is 10 m/s², what is its value at a depth of R/2 (where R is Earth's radius)?
Select the correct option:
Solution
Incorrect! Answer:
5 m/s²
- Gravity Variation with Depth: gd=g(1−Rd).
- Identify Depth: d=R/2.
- Calculation:
- gd=10×(1−RR/2).
- gd=10×(1−0.5).
- Result: gd=5 m/s2.
- Context: Gravitation inside the Earth decreases linearly with distance from the center, reaching zero at d=R (the Earth's core).
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About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- free fall
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
5 m/s²
- Gravity Variation with Depth: gd=g(1−Rd).
- Identify Depth: d=R/2.
- Calculation:
- gd=10×(1−RR/2).
- gd=10×(1−0.5).
- Result: gd=5 m/s2.
- Context: Gravitation inside the Earth decreases linearly with distance from the center, reaching zero at d=R (the Earth's core).
This easy difficulty physics question is from the chapter gravitation, covering the topic of free fall. It appeared in the 2025 exam.
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