Force On Wire
Easyphysics
A straight wire of length 0.5m carries a current of 2A. It is placed in a uniform magnetic field of 0.4T perpendicular to the wire. The force experienced by the wire is:
Current Carrying Wire
Select the correct option:
Solution
Incorrect! Answer:
0.4 N
- Force Formula: The magnetic force on a current-carrying wire is F=BILsinθ.
- Identify Parameters: B=0.4 T, I=2 A, L=0.5 m, and θ=90∘.
- Calculation: F=0.4×2×0.5×sin(90∘)=0.4×1=0.4 N
- Conclusion: The force magnitude is 0.4 N.
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About This Question
- Subject
- physics
- Chapter
- moving charges and magnetism
- Topic
- force on wire
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.4 N
- Force Formula: The magnetic force on a current-carrying wire is F=BILsinθ.
- Identify Parameters: B=0.4 T, I=2 A, L=0.5 m, and θ=90∘.
- Calculation: F=0.4×2×0.5×sin(90∘)=0.4×1=0.4 N
- Conclusion: The force magnitude is 0.4 N.
This easy difficulty physics question is from the chapter moving charges and magnetism, covering the topic of force on wire. It appeared in the 2025 exam.
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