Faraday's Laws

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How many grams of copper will be deposited at the cathode when 0.5 F of electricity is passed through CuSO₄ solution? (Atomic mass of Cu = 63.5)

RankGuru · Accepted Answer

According to **Faraday's first law of electrolysis**, the mass deposited is proportional to the quantity of electricity.
- Cathode Reaction: $Cu^{2+} + 2e^- 	o Cu(s)$
- Electricity Required: To deposit $1$ mole ($63.5 	ext{ g}$) of $Cu$, $2$ moles of electrons ($2 	ext{ Faradays}$) are required.
- Relationship: $2 	ext{ F} 	o 63.5 	ext{ g } Cu$
- For **$0.5 	ext{ F}$**: $mass = \frac{63.5}{2} 	imes 0.5 = 15.875 	ext{ g} \approx 15.9 	ext{ g}$.

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