Faraday's Laws
How many grams of copper will be deposited at the cathode when 0.5 F of electricity is passed through CuSO₄ solution? (Atomic mass of Cu = 63.5)
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About This Question
- Subject
- chemistry
- Chapter
- redox reactions and electrochemistry
- Topic
- faraday's laws
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
15.9 g
According to Faraday's first law of electrolysis, the mass deposited is proportional to the quantity of electricity.
- Cathode Reaction: Cu2++2e−→Cu(s)
- Electricity Required: To deposit 1 mole (63.5 g) of Cu, 2 moles of electrons (2 Faradays) are required.
- Relationship: 2 F→63.5 g Cu
- For 0.5 F: mass=263.5×0.5=15.875 g≈15.9 g.
This medium difficulty chemistry question is from the chapter redox reactions and electrochemistry, covering the topic of faraday's laws. It appeared in the 2025 exam.
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