Exact De
Mediummathematics
The differential equation M dx + N dy = 0 is exact if
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Solution
Incorrect! Answer:
∂M/∂y = ∂N/∂x
- Definition: An equation is 'exact' if it is the total differential of some function u(x,y), i.e., du=Mdx+Ndy.
- Symmetry Condition: For du=fxdx+fydy, Clairaut's theorem states that fxy=fyx for continuous functions.
- Translation: Since M=∂x∂u and N=∂y∂u, we must have:
- ∂y∂M=∂x∂y∂2u and ∂x∂N=∂y∂x∂2u.
- Conclusion: The necessary and sufficient condition is ∂y∂M=∂x∂N.
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About This Question
- Subject
- mathematics
- Chapter
- differential equations
- Topic
- exact de
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
∂M/∂y = ∂N/∂x
- Definition: An equation is 'exact' if it is the total differential of some function u(x,y), i.e., du=Mdx+Ndy.
- Symmetry Condition: For du=fxdx+fydy, Clairaut's theorem states that fxy=fyx for continuous functions.
- Translation: Since M=∂x∂u and N=∂y∂u, we must have:
- ∂y∂M=∂x∂y∂2u and ∂x∂N=∂y∂x∂2u.
- Conclusion: The necessary and sufficient condition is ∂y∂M=∂x∂N.
This medium difficulty mathematics question is from the chapter differential equations, covering the topic of exact de. It appeared in the 2025 exam.
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