Escape Velocity
What is the escape velocity from Earth's surface? (g = 10 m/s², R = 6.4 × 10⁶ m)
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About This Question
- Subject
- physics
- Chapter
- gravitation
- Topic
- escape velocity
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
11.2 km/s
- Definition: Escape velocity (ve) is the minimum speed needed for a free, non-propelled object to escape from the gravitational influence of a primary body.
- Formula: ve=R2GM=2gR.
- Apply Data:
- g=10 m/s2.
- R=6.4×106 m.
- Calculation:
- ve=2×10×6.4×106=128×106.
- ve≈11313 m/s.
- Standard Value: For g=9.8, it is exactly 11.2 km/s. With g=10, it is closer to 11.3 km/s. Result is 11.2 km/s.
This medium difficulty physics question is from the chapter gravitation, covering the topic of escape velocity. It appeared in the 2025 exam.
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