Skip to content

Equilibrium Constant - Temperature Dependence

Mediumchemistry

For an endothermic reaction at 400 K, K_c = 2.0 \times 10^{-3}. When the temperature is raised to 600 K, which of the following best describes the change in K_c?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

More equilibrium Practice Questions

HardJEE_ADVANCED

At 700 K, 0.4 mol of H_2 and 0.4 mol of I_2 are placed in a 1 L flask. At equilibrium, the flask con...

View Solution→
EasyJEE_MAIN

The solubility of BaSO_4 in water at 25°C is 1.05 \times 10^{-5} mol L^{-1}. What is the value of it...

View Solution→
MediumJEE_MAIN

The solubility of AgCl in 0.1 M NaCl solution is much lower than its solubility in pure water. If K_...

View Solution→
EasyJEE_MAIN

According to the Lewis acid-base theory, which of the following species acts as a Lewis acid in the ...

View Solution→
HardJEE_ADVANCED

The K_{sp} of Mg(OH)_2 is 1.2 \times 10^{-11} at 25°C. What is the minimum concentration of OH^- ion...

View Solution→
MediumJEE_MAIN

At 600 K, K_c for the reaction H_2(g) + I_2(g) \rightleftharpoons 2HI(g) is 64. If [H_2] = 0.5 M, [I...

View Solution→
MediumJEE_MAIN

At equilibrium, 20% of N_2O_4 is dissociated into NO_2 according to N_2O_4(g) \rightleftharpoons 2NO...

View Solution→
EasyJEE_MAIN

At 25°C, the ionic product of water K_w = 1.0 \times 10^{-14}. What is the pOH of a solution whose [...

View Solution→
HardJEE_ADVANCED

In a closed vessel at 800 K, SO_3 partially dissociates: 2SO_3(g) \rightleftharpoons 2SO_2(g) + O_2(...

View Solution→
MediumJEE_MAIN

For the reaction CO(g) + 3H_2(g) \rightleftharpoons CH_4(g) + H_2O(g), what will happen to the equil...

View Solution→
EasyJEE_MAIN

Which of the following aqueous salt solutions will be basic (pH > 7) at 25°C due to hydrolysis of it...

View Solution→
MediumJEE_MAIN

In the reaction H_2O + NH_3 \rightleftharpoons OH^- + NH_4^+, which pair correctly identifies the co...

View Solution→

Browse all equilibrium questions →

About This Question

Subject
chemistry
Chapter
equilibrium
Topic
equilibrium constant - temperature dependence
Difficulty
Medium
Year
2025
Tags
temperature effect on Kcvan't Hoff equationendothermic equilibriumthermodynamics of equilibriumGibbs free energy

Solution

Correct Answer:

The temperature dependence of the equilibrium constant is given by the van't Hoff equation: d(ln K)/dT = \Delta H° / RT^2. For an endothermic reaction, \Delta H° > 0, so d(ln K)/dT > 0, meaning K increases as temperature increases. Raising temperature for an endothermic reaction provides the energy needed to drive the forward reaction further, shifting equilibrium to the right and increasing the ratio of products to reactants at the new equilibrium, which means K_c increases. Option A is incorrect reasoning: while Le Chatelier's principle says the system opposes the temperature rise by absorbing heat, this means the endothermic forward reaction is favoured, which increases K_c — not decreases it. Option C is fundamentally wrong; K_c is temperature-dependent and changes with temperature, unlike rate constants which change differently. Option D is the opposite of reality for endothermic reactions; K_c increases with temperature for endothermic reactions and decreases for exothermic ones. This van't Hoff relationship is a critical NCERT thermodynamic concept linking \Delta G° = -RT ln K to temperature. Plausibility check: at higher temperature, the new K_c > 2.0 \times 10^{-3} for an endothermic process, consistent with our conclusion.

This medium difficulty chemistry question is from the chapter equilibrium, covering the topic of equilibrium constant - temperature dependence. It appeared in the 2025 exam.

Looking for more practice? Explore all chemistry questions or browse equilibrium questions on RankGuru.