equations of motion

Question

Particle with initial velocity 10 m/s decelerates uniformly at 2 m/s². Time to stop:

RankGuru · Accepted Answer

Using the first equation of motion:
$v = u + a t$
Given:
- Initial velocity $u = 10 	ext{ m/s}$
- Final velocity $v = 0 	ext{ (stops)}$
- Acceleration $a = -2 	ext{ m/s}^2 	ext{ (deceleration)}$
Substituting the values:
$0 = 10 - 2t$
$2t = 10 \implies t = 5 	ext{ s}$.

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