Equations Of Motion

Easyphysics

Particle with initial velocity 10 m/s decelerates uniformly at 2 m/s². Time to stop:

Select the correct option:

5 s

10 s

20 s

2 s

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject: physics
Chapter: kinematics
Topic: equations of motion
Difficulty: Easy
Year: 2025

Solution

Correct Answer:

5 s

Using the first equation of motion: $v = u + a t$ Given:

Initial velocity $u = 10 m/s$
Final velocity $v = 0 (stops)$
Acceleration $a = - 2 m/s^{2} (deceleration)$ Substituting the values: $0 = 10 - 2 t$ $2 t = 10 ⟹ t = 5 s$ .

This easy difficulty physics question is from the chapter kinematics, covering the topic of equations of motion. It appeared in the 2025 exam.

Looking for more practice? Explore all physics questions or browse kinematics questions on RankGuru.

Rank Guru

Equations Of Motion

Select the correct option:

Solution

🔒 Solution Hidden from View

More equations of motion Practice Questions

A car accelerates uniformly from rest to a velocity of 25 m/s in 5 seconds. What is the distance cov...

Stopping distance for particle in KN-010 is:

A car accelerates uniformly from rest at 2 m/s². Distance in 5 s is:

About This Question

Solution