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Equation Of A Line In Space

Easymathematics

Consider the line passing through the point (2, -1, 3) and parallel to the vector 4i + 0j - 3k in three-dimensional space.

Select the correct option:

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About This Question

Subject
mathematics
Chapter
three dimensional geometry
Topic
equation of a line in space
Difficulty
Easy
Year
2025
Tags
advanced-calculus-drillline equationsymmetric formdirection ratios3d geometry

Solution

Correct Answer:

The relevant standard form is the symmetric (Cartesian) equation of a line through a point (x_0, y_0, z_0) with direction ratios (a, b, c): (x-x_0)/a = (y-y_0)/b = (z-z_0)/c. This representation is a JEE Advanced staple for describing lines in space. Here the point is (2, -1, 3), so x_0 = 2, y_0 = -1, z_0 = 3, and the direction ratios come straight from the parallel vector, giving (a, b, c) = (4, 0, -3). Substituting yields (x-2)/4 = (y+1)/0 = (z-3)/(-3); the zero denominator is conventional shorthand meaning y + 1 = 0 along the line. Option two negates the coordinates of the point incorrectly. Option three uses the point's coordinates as direction ratios, confusing position with direction. Option four scrambles point and direction values entirely. This is the direct application of the point-direction line equation. Plausibility check: substituting the given point makes every fraction equal to zero simultaneously, confirming the point lies on the line as required.

This easy difficulty mathematics question is from the chapter three dimensional geometry, covering the topic of equation of a line in space. It appeared in the 2025 exam.

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