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Equal Roots Condition

Mediummathematics

The values of the real parameter m for which the quadratic equation (m + 1)x^2 + 2(m + 3)x + (m + 8) = 0 has equal roots are obtained from which condition and solution?

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About This Question

Subject
mathematics
Chapter
complex numbers and quadratic equations
Topic
equal roots condition
Difficulty
Medium
Year
2025
Tags
advanced-calculus-drillequal-rootsdiscriminant-zeroparametric-quadraticrepeated-root

Solution

Correct Answer:

Equal roots of a quadratic require the discriminant to vanish, the defining JEE Advanced condition for a repeated root. For (m + 1)x^2 + 2(m + 3)x + (m + 8) = 0, the discriminant is [2(m + 3)]^2 - 4(m + 1)(m + 8) = 0. Expanding, 4(m + 3)^2 - 4(m + 1)(m + 8) = 0, divide by 4: (m^2 + 6m + 9) - (m^2 + 9m + 8) = 0, giving 6m + 9 - 9m - 8 = -3m + 1 = 0, so m = 1/3. We require m + 1 ≠ 0 for a genuine quadratic, and m = 1/3 satisfies that. Option m = -1 makes the equation linear, not quadratic. Option m = 0 from sum of roots is irrelevant to equal roots. Option no real m exists contradicts the linear discriminant equation. Hence m = 1/3. Plausibility check: substituting m = 1/3 makes the discriminant exactly zero by construction, guaranteeing a single repeated real root, consistent with the equal-roots requirement. Equating the discriminant to zero is the precise algebraic statement that a parabola touches the x-axis at a single repeated root, geometrically a tangency condition. The parametric setup must also exclude any value that would destroy the leading coefficient and collapse the equation to a linear one, a subtlety that examiners deliberately embed to test whether the quadratic structure has been preserved.

This medium difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of equal roots condition. It appeared in the 2025 exam.

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