Energy Partition In Diatomic Gas
An ideal diatomic gas with rigid molecules is in thermal equilibrium; what fraction of its total internal energy is contributed by translational motion of the molecules?
Select the correct option:
Solution
0.6
A rigid diatomic molecule has five active degrees of freedom: three translational and two rotational. By the law of equipartition, each degree of freedom stores the same average energy 21kBT, so the total internal energy divides equally among the five modes. The translational share comes from three of these five, giving a fraction 53=0.6. Equivalently, translational energy is 23kBT out of a total 25kBT per molecule. This partition is independent of temperature, because raising the temperature scales the energy in every mode by the same amount and leaves the ratios unchanged. The value 0.4 mistakenly assigns the larger share to rotation, reversing the count. The value 1.0 ignores rotational energy entirely, as if the gas were monatomic. The value 0.33 wrongly divides three translational modes by an assumed nine total degrees of freedom. This is a direct consequence of the NCERT equipartition theorem applied to molecular structure, and notably only the translational part contributes to pressure and temperature. As a plausibility check, the rotational fraction must be the complement 2/5=0.4, and the two fractions sum to unity, confirming that translational motion accounts for exactly 60 % of the internal energy of a rigid diatomic gas.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- energy partition in diatomic gas
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
0.6
A rigid diatomic molecule has five active degrees of freedom: three translational and two rotational. By the law of equipartition, each degree of freedom stores the same average energy 21kBT, so the total internal energy divides equally among the five modes. The translational share comes from three of these five, giving a fraction 53=0.6. Equivalently, translational energy is 23kBT out of a total 25kBT per molecule. This partition is independent of temperature, because raising the temperature scales the energy in every mode by the same amount and leaves the ratios unchanged. The value 0.4 mistakenly assigns the larger share to rotation, reversing the count. The value 1.0 ignores rotational energy entirely, as if the gas were monatomic. The value 0.33 wrongly divides three translational modes by an assumed nine total degrees of freedom. This is a direct consequence of the NCERT equipartition theorem applied to molecular structure, and notably only the translational part contributes to pressure and temperature. As a plausibility check, the rotational fraction must be the complement 2/5=0.4, and the two fractions sum to unity, confirming that translational motion accounts for exactly 60 % of the internal energy of a rigid diatomic gas.
This hard difficulty physics question is from the chapter kinetic theory of gases, covering the topic of energy partition in diatomic gas. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse kinetic theory of gases questions on RankGuru.