electrolyte effect on colligative

Question

Which aqueous solute produces greatest freezing point depression per mole?

RankGuru · Accepted Answer

1. **Equation**: $\Delta T_f = i 	imes K_f 	imes m$.
2. **The Goal**: For the same molality ($1$ mole per kg), we need to find the largest van't Hoff factor (**$i$**).
3. **Particle Count**:
   - **Urea**: Molecular. $i = 1$.
   - **$KCl$**: $K^+ + Cl^- 	o$ $2$ particles. $i = 2$.
   - **$CaCl_2$**: $Ca^{2+} + 2 Cl^- 	o$ $3$ particles. $i = 3$.
   - **$Al_2(SO_4)_3$**: $2 Al^{3+} + 3 SO_4^{2-} 	o$ **$5$ particles**. $i = 5$.
4. **Conclusion**: Since $Al_2(SO_4)_3$ yields the highest number of particles, it creates the largest change in Colligative properties.

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electrolyte effect on colligative

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