Electrolyte Effect On Colligative
Which aqueous solute produces greatest freezing point depression per mole?
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About This Question
- Subject
- chemistry
- Chapter
- solutions
- Topic
- electrolyte effect on colligative
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Al2(SO4)3
- Equation: ΔTf=i×Kf×m.
- The Goal: For the same molality (1 mole per kg), we need to find the largest van't Hoff factor (i).
- Particle Count:
- Urea: Molecular. i=1.
- KCl: K++Cl−→ 2 particles. i=2.
- CaCl2: Ca2++2Cl−→ 3 particles. i=3.
- Al2(SO4)3: 2Al3++3SO42−→ 5 particles. i=5.
- Conclusion: Since Al2(SO4)3 yields the highest number of particles, it creates the largest change in Colligative properties.
This medium difficulty chemistry question is from the chapter solutions, covering the topic of electrolyte effect on colligative. It appeared in the 2025 exam.
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