Electric Potential And Potential Energy
At a radial distance of 0.5 m from an isolated point charge of 5 nanocoulomb the potential takes a definite value, so what is it?
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About This Question
- Subject
- physics
- Chapter
- electrostatics
- Topic
- electric potential and potential energy
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
90 V
Electric potential due to a point charge is V=4πε01rq, with 4πε01=9×109 Nm2/C2, a formula stated in NCERT Class 12, Chapter 2 (Electrostatic Potential and Capacitance). Here q=5×10−9 C and r=0.5 m. Substituting, V=9×109×0.55×10−9. The product 9×109×5×10−9=45, and dividing by 0.5 gives V=90 V. The value 45 V is wrong because it forgets to divide by r=0.5, effectively using r=1 m. The value 180 V is wrong because it divides by 0.25, mistakenly squaring the distance as if computing a field. The value 9 V is wrong because it drops the factor of 5 from the charge. As potential is a scalar, no direction enters the result. A sign and magnitude check confirms a positive charge gives positive potential, and nano-coulomb charges at half a metre yielding tens of volts is entirely reasonable.
This easy difficulty physics question is from the chapter electrostatics, covering the topic of electric potential and potential energy. It appeared in the 2025 exam.
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