electric field

Question

A point charge of +2 μC creates an electric field. What is the magnitude of the field at a distance of 0.1 m from the charge? (k = 9 × 10⁹ N·m²/C²)

RankGuru · Accepted Answer

1. **Definition**: The electric field ($E$) at a point is the force per unit charge at that point.
   - Formula: $E = k \frac{q}{r^2}$.
2. **Data**:
   - $q = 2 	imes 10^{-6} 	ext{ C}$.
   - $r = 0.1$ m.
3. **Computation**:
   - $E = \frac{9 	imes 10^9 	imes 2 	imes 10^{-6}}{(0.1)^2}$
   - $E = \frac{18 	imes 10^3}{0.01}$.
4. **Final Value**: $E = 1.8 	imes 10^6 	ext{ N/C}$.
5. **Direction**: For a positive charge, the field points **radially outward**.

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