Earth's Magnetism And Angle Of Dip
At a certain location the horizontal component of the Earth's magnetic field is 0.3G and the vertical component is 0.33G. What is the angle of dip at this place?
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About This Question
- Subject
- physics
- Chapter
- magnetic effects of current and magnetism
- Topic
- earth's magnetism and angle of dip
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
60∘
The Earth's magnetic field at a place is described by three elements: declination, the horizontal component H, and the angle of dip δ. The dip is the angle the total field makes with the horizontal, related to the components by tanδ=HV, where V is the vertical component. Substituting V=0.33G and H=0.3G, we get tanδ=0.30.33=3, so δ=tan−1(3)=60∘. The option 30∘ corresponds to tanδ=31, which would invert the component ratio. The option 45∘ would require equal vertical and horizontal components. The option 90∘ would occur only at the magnetic poles, where the horizontal component vanishes. This treatment of the elements of Earth's magnetism follows the NCERT magnetism chapter, where a dip needle and compass measure these quantities. A sanity check confirms that a vertical component larger than the horizontal one gives a dip greater than 45∘, consistent with the obtained 60∘. These elements vary systematically over the globe, with the dip angle increasing from zero at the magnetic equator to ninety degrees at the magnetic poles, where a freely suspended needle points straight down. Mapping declination, dip, and horizontal intensity is the business of geomagnetism, and navigators historically corrected compass readings for the local declination, underscoring how these abstract field components have very concrete practical consequences for orientation on Earth.
This medium difficulty physics question is from the chapter magnetic effects of current and magnetism, covering the topic of earth's magnetism and angle of dip. It appeared in the 2025 exam.
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