Distance From Point To Plane
Mediummathematics
The perpendicular distance of point (x₁, y₁, z₁) from plane Ax + By + Cz + D = 0 is
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Solution
Incorrect! Answer:
|Ax₁ + By₁ + Cz₁ + D| / √(A² + B² + C²)
- Definition: The length of the perpendicular from point P(x1,y1,z1) to the plane Ax+By+Cz+D=0 is the shortest distance.
- Vector Formula: If the plane is r⋅n+D=0 and the point is a, then distance d=[∣n∣∣a⋅n+D∣.
- Cartesian Expansion: Substituting a=(x1,y1,z1) and n=(A,B,C): d=A2+B2+C2∣Ax1+By1+Cz1+D∣.
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About This Question
- Subject
- mathematics
- Chapter
- three dimensional geometry
- Topic
- distance from point to plane
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
|Ax₁ + By₁ + Cz₁ + D| / √(A² + B² + C²)
- Definition: The length of the perpendicular from point P(x1,y1,z1) to the plane Ax+By+Cz+D=0 is the shortest distance.
- Vector Formula: If the plane is r⋅n+D=0 and the point is a, then distance d=[∣n∣∣a⋅n+D∣.
- Cartesian Expansion: Substituting a=(x1,y1,z1) and n=(A,B,C): d=A2+B2+C2∣Ax1+By1+Cz1+D∣.
This medium difficulty mathematics question is from the chapter three dimensional geometry, covering the topic of distance from point to plane. It appeared in the 2025 exam.
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