Dispersion By A Prism
A thin prism of small refracting angle has refractive indices 1.532 for violet light and 1.514 for red light, with a mean index of 1.523 for yellow light. Calculate the dispersive power of the prism material.
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- dispersion by a prism
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
0.034
Dispersive power measures how strongly a material spreads colours relative to its average bending, defined as ω=ny−1nv−nr, where nv, nr and ny are the violet, red and mean (yellow) refractive indices. Crucially the prism angle cancels for a thin prism, so ω depends only on the material. The spread of indices is nv−nr=1.532−1.514=0.018, and the mean deviation factor is ny−1=1.523−1=0.523. Therefore ω=0.5230.018≈0.034. The deeper significance is that dispersive power separates the two distinct roles a prism plays: (ny−1)A governs the average bending of the beam, while (nv−nr)A governs the spreading of colours; their ratio strips away the geometry and leaves a pure material property. This is exactly why an achromatic combination pairs a crown-glass prism with a flint-glass prism of differing dispersive powers so their colour spreads cancel while a net deviation survives. The value 0.018 is wrong because it is only the numerator nv−nr and omits division by the mean term. The value 0.090 is wrong as it represents the angular dispersion (nv−nr)A for a 5° prism, not a dimensionless power. The value 0.052 is wrong because it mistakenly divides by nv−1 inconsistently. This is the NCERT definition underlying achromatic prism combinations. A consistency check confirms dispersive power is a small dimensionless number around a few percent for ordinary crown glass, matching 0.034.
This hard difficulty physics question is from the chapter optics, covering the topic of dispersion by a prism. It appeared in the 2025 exam.
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